32x^2+60x+13=0

Solution for 32x^2+60x+13=0 equation:

32x^2+60x+13=0

a = 32; b = 60; c = +13;
Δ = b2-4ac
Δ = 602-4·32·13
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-44}{2*32}=\frac{-104}{64}
=-1+5/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+44}{2*32}=\frac{-16}{64}
=-1/4
$